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Limewater Calcium Hydroxide

AS Chemistry Coursework - To determine the concentration of a Limewater Solution

Aim

To determine the concentration a 250 cm3 limewater solution, this contains approximately 1g dm-3 of calcium hydroxide. Also known is the concentration of HCL at 2.00mol dm-3.

Introduction

A titration method will be used to work out the concentration of the limewater

But before the concentration of the limewater can be worked out, the correct concentration of HCL must be worked out and an ideal indicator used in the titration method must be chosen.

HCL Concentration

The known concentration of limewater is 1g dm-3 and the concentration of the HCL is 2.00 mol dm-3. The concentration of HCL too high and must be reduced by dilution.

Indicator

Indicators in titrations are used to determine the end point of the neutralization of the reaction of an analyte solution (unknown concentration) by the addition of a titrant solution (known concentration and volume). The end-point is shown by the change in colour of the indicator present in the analyte solution.

An ideal indicator should:

The indicator ‘Phenolphthalein' has these ideal properties and will be suitable for the titration. In this titration, the regent or titrant solution will be HCL and the analyte solution will be the limewater, the phenolphthalein indicator will be placed in the limewater [Ca(OH)2(aq)]. In a base, phenolphthalein changes colour to ‘pink' and when in a neutral solution, it will become colourless. The reaction:

Ca(OH)2(aq) + 2HCl(aq) CaCl2(aq) + 2H2O(l)

Is primarily a base [Ca(OH)2(aq)] plus an acid [2HCl(aq)] which produces water and a salt [CaCl2(aq)] (both together as a solution). Therefore in his titration, as HCL is added to Ca(OH)2(aq) the indicator should turn from ‘pink' to colourless' upon the complete neutralization of Ca(OH)2(aq).

Preparation

Before the titration can begin, we must find the correct concentration of HCl worked out from the giving concentration of Ca(OH)2(aq). However the Ca(OH)2(aq) is giving in

‘grams dm-3' and HCL is giving in ‘mol dm-3', thus one of the concentration has to be converted to the same units as the other.

Limewater [Ca(OH)2(aq) ] converted from ‘grams dm-3' to ‘mol dm-3'

Ca(OH)2(aq) has a concentration of 1g dm-3, which means that 1 gram of Ca(OH)2(aq) is dissolved in 1 dm-3 of water or 1000cm-3.

Using the equation Moles = Mass/RMM we can convert the units.

Moles = Mass/RMM

Mass Ca(OH)2(aq) = 1 gram

RMM Ca(OH)2(aq) = 40 + 2(16 + 1) = 74

Moles = 1 / 74 = 0.0135 moldm-3 (3 sig)

Concentration of HCL

The Limewater [Ca(OH)2(aq) ] has now, the same units of concentration as HCL.

Ca(OH)2(aq) + 2HCl(aq) CaCl2(aq) + 2H2O(l)

This reaction shows that 2 moles of HCL are reacting with 1 mole

Limewater [Ca(OH)2(aq) ]. Therefore the concentration of HCL must be double that of Limewater [Ca(OH)2(aq) ] at approx 0.0200 moldm-3, as it would be impractical to get it at exactly at 0.270 moldm-3. This means that the HCL must be diluted by a factor of 100, again this also impractical, so it will be twice by a factor of 10.

Hazards and Safety

Key points on safety and hazards when performing the experiment.

Hazards

Safety

Method to dilute HCL

Equipment and Chemicals

Method

Method of Titration

Fig.1

Equipment and Chemicals 

Test

Start Value (cm3)

End Value (cm3)

Titration

(cm3)

1st (Rough)

0.00

2nd

0.00

3rd

0.00

4th

0.00

5th

0.00

Average

0.00

250cm3 of the 0.002moldm-3 of

Fig.2

HCL from the dilution method.

of the unknown limewater [Ca(OH)2(aq) ]

solution.

Method

 

Results

The results need to be processed. The titration column is difference between the start point value and the end point value The units of all the results need to be at 2 decimal places and the averages taken the start point value, the end point value and the titration value for excluding the rough titration results.

Test

Start Value (cm3)

End Value (cm3)

Titration

(cm3)

1st (Rough)

0.00

2nd

0.00

3rd

0.00

4th

0.00

5th

0.00

Average

0.00

Analysis

The average titration (represented by X in the table below) will be in cm-3 and will need to be converted into dm3 to make its easier to use in calculations. To convert the value from cm3 to dm3, divide the value by 1000.

Xcm3 / 1000 = Xdm3

HCl

Ca(OH)2

Moles / moles

?

?

Volume / dm3

X

0.025

Conc. moldm-3

0.02

?

Using the equation for a moles in a solution

Moles = Concentration x Volume

The moles of HCL can now be worked out as the concentration is now known and the volume of HCL is

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